Elijah and Jenson shared some pens. Elijah took
511 of the pens. After Elijah lost 22 pens, Jenson had twice as many pens as Elijah. How many pens did Jenson have in the end?
|
Elijah |
Jenson |
Before |
5 u |
6 u |
Change |
- 22 |
|
After |
1x3 = 3 u |
2x3 = 6 u |
The number of pens that Jenson had remains the same. Make the number of pens that Jenson had the same. LCM of 6 and 2 is 6.
Number of pens that Elijah lost
= 5 u - 3 u
= 2 u
2 u = 22
1 u = 22 ÷ 2 = 11
Number of pens that Jenson had in the end
= 6 u
= 6 x 11
= 66
Answer(s): 66