Seth and Cody shared some buttons. Seth took
57 of the buttons. After Seth lost 20 buttons, Cody had twice as many buttons as Seth. How many buttons did Cody have in the end?
| |
Seth |
Cody |
| Before |
5 u |
2 u |
| Change |
- 20 |
|
| After |
1x1 =
1 u |
2x1 =
2 u |
The number of buttons that Cody had remains the same. Make the number of buttons that Cody had the same. LCM of 2 and 2 is 2.
Number of buttons that Seth lost
= 5 u - 1 u
= 4 u
4 u = 20
1 u = 20 ÷ 4 = 5
Number of buttons that Cody had in the end
= 2 u
= 2 x 5
= 10
Answer(s): 10
