Gabriel and Charlie shared some marbles. Gabriel took
511 of the marbles. After Gabriel lost 12 marbles, Charlie had thrice as many marbles as Gabriel. How many marbles did Charlie have in the end?
|
Gabriel |
Charlie |
Before |
5 u |
6 u |
Change |
- 12 |
|
After |
1x2 = 2 u |
3x2 = 6 u |
The number of marbles that Charlie had remains the same. Make the number of marbles that Charlie had the same. LCM of 6 and 3 is 6.
Number of marbles that Gabriel lost
= 5 u - 2 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of marbles that Charlie had in the end
= 6 u
= 6 x 4
= 24
Answer(s): 24