Warren and Howard shared some buttons. Warren took
511 of the buttons. After Warren lost 12 buttons, Howard had thrice as many buttons as Warren. How many buttons did Howard have in the end?
|
Warren |
Howard |
Before |
5 u |
6 u |
Change |
- 12 |
|
After |
1x2 = 2 u |
3x2 = 6 u |
The number of buttons that Howard had remains the same. Make the number of buttons that Howard had the same. LCM of 6 and 3 is 6.
Number of buttons that Warren lost
= 5 u - 2 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of buttons that Howard had in the end
= 6 u
= 6 x 4
= 24
Answer(s): 24