Albert and George shared some buttons. Albert took
511 of the buttons. After Albert lost 21 buttons, George had thrice as many buttons as Albert. How many buttons did George have in the end?
|
Albert |
George |
Before |
5 u |
6 u |
Change |
- 21 |
|
After |
1x2 = 2 u |
3x2 = 6 u |
The number of buttons that George had remains the same. Make the number of buttons that George had the same. LCM of 6 and 3 is 6.
Number of buttons that Albert lost
= 5 u - 2 u
= 3 u
3 u = 21
1 u = 21 ÷ 3 = 7
Number of buttons that George had in the end
= 6 u
= 6 x 7
= 42
Answer(s): 42