Cole and Seth shared some stickers. Cole took
511 of the stickers. After Cole lost 20 stickers, Seth had twice as many stickers as Cole. How many stickers did Seth have in the end?
|
Cole |
Seth |
Before |
5 u |
6 u |
Change |
- 20 |
|
After |
1x3 = 3 u |
2x3 = 6 u |
The number of stickers that Seth had remains the same. Make the number of stickers that Seth had the same. LCM of 6 and 2 is 6.
Number of stickers that Cole lost
= 5 u - 3 u
= 2 u
2 u = 20
1 u = 20 ÷ 2 = 10
Number of stickers that Seth had in the end
= 6 u
= 6 x 10
= 60
Answer(s): 60