Carl and Simon shared some beads. Carl took
37 of the beads. After Carl lost 14 beads, Simon had four times as many beads as Carl. How many beads did Simon have in the end?
| |
Carl |
Simon |
| Before |
3 u |
4 u |
| Change |
- 14 |
|
| After |
1x1 =
1 u |
4x1 =
4 u |
The number of beads that Simon had remains the same. Make the number of beads that Simon had the same. LCM of 4 and 4 is 4.
Number of beads that Carl lost
= 3 u - 1 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Number of beads that Simon had in the end
= 4 u
= 4 x 7
= 28
Answer(s): 28
