Peter and Xavier shared some erasers. Peter took
37 of the erasers. After Peter lost 16 erasers, Xavier had four times as many erasers as Peter. How many erasers did Xavier have in the end?
| |
Peter |
Xavier |
| Before |
3 u |
4 u |
| Change |
- 16 |
|
| After |
1x1 =
1 u |
4x1 =
4 u |
The number of erasers that Xavier had remains the same. Make the number of erasers that Xavier had the same. LCM of 4 and 4 is 4.
Number of erasers that Peter lost
= 3 u - 1 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Number of erasers that Xavier had in the end
= 4 u
= 4 x 8
= 32
Answer(s): 32
