Neave and David shared some erasers. Neave took
57 of the erasers. After Neave lost 16 erasers, David had twice as many erasers as Neave. How many erasers did David have in the end?
|
Neave |
David |
Before |
5 u |
2 u |
Change |
- 16 |
|
After |
1x1 = 1 u |
2x1 = 2 u |
The number of erasers that David had remains the same. Make the number of erasers that David had the same. LCM of 2 and 2 is 2.
Number of erasers that Neave lost
= 5 u - 1 u
= 4 u
4 u = 16
1 u = 16 ÷ 4 = 4
Number of erasers that David had in the end
= 2 u
= 2 x 4
= 8
Answer(s): 8