Justin and Mark shared some pens. Justin took
511 of the pens. After Justin lost 16 pens, Mark had twice as many pens as Justin. How many pens did Mark have in the end?
|
Justin |
Mark |
Before |
5 u |
6 u |
Change |
- 16 |
|
After |
1x3 = 3 u |
2x3 = 6 u |
The number of pens that Mark had remains the same. Make the number of pens that Mark had the same. LCM of 6 and 2 is 6.
Number of pens that Justin lost
= 5 u - 3 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Number of pens that Mark had in the end
= 6 u
= 6 x 8
= 48
Answer(s): 48