Julian and Vaidev shared some beads. Julian took
511 of the beads. After Julian lost 22 beads, Vaidev had twice as many beads as Julian. How many beads did Vaidev have in the end?
|
Julian |
Vaidev |
Before |
5 u |
6 u |
Change |
- 22 |
|
After |
1x3 = 3 u |
2x3 = 6 u |
The number of beads that Vaidev had remains the same. Make the number of beads that Vaidev had the same. LCM of 6 and 2 is 6.
Number of beads that Julian lost
= 5 u - 3 u
= 2 u
2 u = 22
1 u = 22 ÷ 2 = 11
Number of beads that Vaidev had in the end
= 6 u
= 6 x 11
= 66
Answer(s): 66