Riordan and Daniel had a total of $336. Riordan gave $37 to Daniel. In return, Daniel gave
13 of his money to Riordan. In the end, Riordan had five times as much money as Daniel. How much money did Riordan have at first?
| |
Riordan |
Daniel |
Total |
| Before |
|
|
$336 |
| Change 1 |
- $37 |
+ $37 |
|
| After 1 |
|
3 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
2 p |
|
Comparing Riordan
and Daniel
in the end |
5 u |
1 u |
$336 |
The total amount that Daniel and Riordan had remains unchanged.
Total amount in the end
= 5 u + 1 u
= 6 u
6 u = 336
1 u = 336 ÷ 6 = 56
Amount that Riordan has in the end
= 5 u
= 5 x 56
= $280
Amount that Daniel has in the end
= 1 u
= $56
2 p = 1 u = 56
1 p = 56 ÷ 2 = 28
Amount that Daniel gave to Riordan
= 1 p
= 1 x 28
= $28
Amount that Riordan had at first
= 280 - 28 + 37
= $289
Answer(s): $289
