Michael and Ivan had a total of $147. Michael gave $44 to Ivan. In return, Ivan gave
18 of his money to Michael. In the end, Michael had twice as much money as Ivan. How much money did Michael have at first?
| |
Michael |
Ivan |
Total |
| Before |
|
|
$147 |
| Change 1 |
- $44 |
+ $44 |
|
| After 1 |
|
8 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
7 p |
|
Comparing Michael
and Ivan
in the end |
2 u |
1 u |
$147 |
The total amount that Ivan and Michael had remains unchanged.
Total amount in the end
= 2 u + 1 u
= 3 u
3 u = 147
1 u = 147 ÷ 3 = 49
Amount that Michael has in the end
= 2 u
= 2 x 49
= $98
Amount that Ivan has in the end
= 1 u
= $49
7 p = 1 u = 49
1 p = 49 ÷ 7 = 7
Amount that Ivan gave to Michael
= 1 p
= 1 x 7
= $7
Amount that Michael had at first
= 98 - 7 + 44
= $135
Answer(s): $135
