Peter and Cody had a total of $210. Peter gave $14 to Cody. In return, Cody gave
16 of his money to Peter. In the end, Peter had six times as much money as Cody. How much money did Peter have at first?
| |
Peter |
Cody |
Total |
| Before |
|
|
$210 |
| Change 1 |
- $14 |
+ $14 |
|
| After 1 |
|
6 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
5 p |
|
Comparing Peter
and Cody
in the end |
6 u |
1 u |
$210 |
The total amount that Cody and Peter had remains unchanged.
Total amount in the end
= 6 u + 1 u
= 7 u
7 u = 210
1 u = 210 ÷ 7 = 30
Amount that Peter has in the end
= 6 u
= 6 x 30
= $180
Amount that Cody has in the end
= 1 u
= $30
5 p = 1 u = 30
1 p = 30 ÷ 5 = 6
Amount that Cody gave to Peter
= 1 p
= 1 x 6
= $6
Amount that Peter had at first
= 180 - 6 + 14
= $188
Answer(s): $188
