Simon and Eric had a total of $336. Simon gave $32 to Eric. In return, Eric gave
18 of his money to Simon. In the end, Simon had twice as much money as Eric. How much money did Simon have at first?
| |
Simon |
Eric |
Total |
| Before |
|
|
$336 |
| Change 1 |
- $32 |
+ $32 |
|
| After 1 |
|
8 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
7 p |
|
Comparing Simon
and Eric
in the end |
2 u |
1 u |
$336 |
The total amount that Eric and Simon had remains unchanged.
Total amount in the end
= 2 u + 1 u
= 3 u
3 u = 336
1 u = 336 ÷ 3 = 112
Amount that Simon has in the end
= 2 u
= 2 x 112
= $224
Amount that Eric has in the end
= 1 u
= $112
7 p = 1 u = 112
1 p = 112 ÷ 7 = 16
Amount that Eric gave to Simon
= 1 p
= 1 x 16
= $16
Amount that Simon had at first
= 224 - 16 + 32
= $240
Answer(s): $240
