Brandon and Michael had a total of $168. Brandon gave $21 to Michael. In return, Michael gave
13 of his money to Brandon. In the end, Brandon had twice as much money as Michael. How much money did Brandon have at first?
| |
Brandon |
Michael |
Total |
| Before |
|
|
$168 |
| Change 1 |
- $21 |
+ $21 |
|
| After 1 |
|
3 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
2 p |
|
Comparing Brandon
and Michael
in the end |
2 u |
1 u |
$168 |
The total amount that Michael and Brandon had remains unchanged.
Total amount in the end
= 2 u + 1 u
= 3 u
3 u = 168
1 u = 168 ÷ 3 = 56
Amount that Brandon has in the end
= 2 u
= 2 x 56
= $112
Amount that Michael has in the end
= 1 u
= $56
2 p = 1 u = 56
1 p = 56 ÷ 2 = 28
Amount that Michael gave to Brandon
= 1 p
= 1 x 28
= $28
Amount that Brandon had at first
= 112 - 28 + 21
= $105
Answer(s): $105
