Ken and George had a total of $210. Ken gave $41 to George. In return, George gave
16 of his money to Ken. In the end, Ken had twice as much money as George. How much money did Ken have at first?
| |
Ken |
George |
Total |
| Before |
|
|
$210 |
| Change 1 |
- $41 |
+ $41 |
|
| After 1 |
|
6 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
5 p |
|
Comparing Ken
and George
in the end |
2 u |
1 u |
$210 |
The total amount that George and Ken had remains unchanged.
Total amount in the end
= 2 u + 1 u
= 3 u
3 u = 210
1 u = 210 ÷ 3 = 70
Amount that Ken has in the end
= 2 u
= 2 x 70
= $140
Amount that George has in the end
= 1 u
= $70
5 p = 1 u = 70
1 p = 70 ÷ 5 = 14
Amount that George gave to Ken
= 1 p
= 1 x 14
= $14
Amount that Ken had at first
= 140 - 14 + 41
= $167
Answer(s): $167
