Tim and Tom had a total of $168. Tim gave $24 to Tom. In return, Tom gave
18 of his money to Tim. In the end, Tim had twice as much money as Tom. How much money did Tim have at first?
| |
Tim |
Tom |
Total |
| Before |
|
|
$168 |
| Change 1 |
- $24 |
+ $24 |
|
| After 1 |
|
8 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
7 p |
|
Comparing Tim
and Tom
in the end |
2 u |
1 u |
$168 |
The total amount that Tom and Tim had remains unchanged.
Total amount in the end
= 2 u + 1 u
= 3 u
3 u = 168
1 u = 168 ÷ 3 = 56
Amount that Tim has in the end
= 2 u
= 2 x 56
= $112
Amount that Tom has in the end
= 1 u
= $56
7 p = 1 u = 56
1 p = 56 ÷ 7 = 8
Amount that Tom gave to Tim
= 1 p
= 1 x 8
= $8
Amount that Tim had at first
= 112 - 8 + 24
= $128
Answer(s): $128
