Pierre and Elijah had a total of $252. Pierre gave $45 to Elijah. In return, Elijah gave
13 of his money to Pierre. In the end, Pierre had six times as much money as Elijah. How much money did Pierre have at first?
|
Pierre |
Elijah |
Total |
Before |
|
|
$252 |
Change 1 |
- $45 |
+ $45 |
|
After 1 |
|
3 p |
|
Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
|
2 p |
|
Comparing Pierre and Elijah in the end |
6 u |
1 u |
$252 |
The total amount that Elijah and Pierre had remains unchanged.
Total amount in the end
= 6 u + 1 u
= 7 u
7 u = 252
1 u = 252 ÷ 7 = 36
Amount that Pierre has in the end
= 6 u
= 6 x 36
= $216
Amount that Elijah has in the end
= 1 u
= $36
2 p = 1 u = 36
1 p = 36 ÷ 2 = 18
Amount that Elijah gave to Pierre
= 1 p
= 1 x 18
= $18
Amount that Pierre had at first
= 216 - 18 + 45
= $243
Answer(s): $243