Dylan and Peter had a total of $176. Dylan gave $50 to Peter. In return, Peter gave
13 of his money to Dylan. In the end, Dylan had thrice as much money as Peter. How much money did Dylan have at first?
| |
Dylan |
Peter |
Total |
| Before |
|
|
$176 |
| Change 1 |
- $50 |
+ $50 |
|
| After 1 |
|
3 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
2 p |
|
Comparing Dylan
and Peter
in the end |
3 u |
1 u |
$176 |
The total amount that Peter and Dylan had remains unchanged.
Total amount in the end
= 3 u + 1 u
= 4 u
4 u = 176
1 u = 176 ÷ 4 = 44
Amount that Dylan has in the end
= 3 u
= 3 x 44
= $132
Amount that Peter has in the end
= 1 u
= $44
2 p = 1 u = 44
1 p = 44 ÷ 2 = 22
Amount that Peter gave to Dylan
= 1 p
= 1 x 22
= $22
Amount that Dylan had at first
= 132 - 22 + 50
= $160
Answer(s): $160
