Ivan and Xavier had a total of $120. Ivan gave $41 to Xavier. In return, Xavier gave
15 of his money to Ivan. In the end, Ivan had five times as much money as Xavier. How much money did Ivan have at first?
| |
Ivan |
Xavier |
Total |
| Before |
|
|
$120 |
| Change 1 |
- $41 |
+ $41 |
|
| After 1 |
|
5 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
4 p |
|
Comparing Ivan
and Xavier
in the end |
5 u |
1 u |
$120 |
The total amount that Xavier and Ivan had remains unchanged.
Total amount in the end
= 5 u + 1 u
= 6 u
6 u = 120
1 u = 120 ÷ 6 = 20
Amount that Ivan has in the end
= 5 u
= 5 x 20
= $100
Amount that Xavier has in the end
= 1 u
= $20
4 p = 1 u = 20
1 p = 20 ÷ 4 = 5
Amount that Xavier gave to Ivan
= 1 p
= 1 x 5
= $5
Amount that Ivan had at first
= 100 - 5 + 41
= $136
Answer(s): $136
