Ahmad and Peter had a total of $160. Ahmad gave $17 to Peter. In return, Peter gave
15 of his money to Ahmad. In the end, Ahmad had four times as much money as Peter. How much money did Ahmad have at first?
| |
Ahmad |
Peter |
Total |
| Before |
|
|
$160 |
| Change 1 |
- $17 |
+ $17 |
|
| After 1 |
|
5 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
4 p |
|
Comparing Ahmad
and Peter
in the end |
4 u |
1 u |
$160 |
The total amount that Peter and Ahmad had remains unchanged.
Total amount in the end
= 4 u + 1 u
= 5 u
5 u = 160
1 u = 160 ÷ 5 = 32
Amount that Ahmad has in the end
= 4 u
= 4 x 32
= $128
Amount that Peter has in the end
= 1 u
= $32
4 p = 1 u = 32
1 p = 32 ÷ 4 = 8
Amount that Peter gave to Ahmad
= 1 p
= 1 x 8
= $8
Amount that Ahmad had at first
= 128 - 8 + 17
= $137
Answer(s): $137
