Sean and Rael had a total of $245. Sean gave $11 to Rael. In return, Rael gave
18 of his money to Sean. In the end, Sean had six times as much money as Rael. How much money did Sean have at first?
| |
Sean |
Rael |
Total |
| Before |
|
|
$245 |
| Change 1 |
- $11 |
+ $11 |
|
| After 1 |
|
8 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
7 p |
|
Comparing Sean
and Rael
in the end |
6 u |
1 u |
$245 |
The total amount that Rael and Sean had remains unchanged.
Total amount in the end
= 6 u + 1 u
= 7 u
7 u = 245
1 u = 245 ÷ 7 = 35
Amount that Sean has in the end
= 6 u
= 6 x 35
= $210
Amount that Rael has in the end
= 1 u
= $35
7 p = 1 u = 35
1 p = 35 ÷ 7 = 5
Amount that Rael gave to Sean
= 1 p
= 1 x 5
= $5
Amount that Sean had at first
= 210 - 5 + 11
= $216
Answer(s): $216
