Bryan and Xavier had a total of $348. Bryan gave $19 to Xavier. In return, Xavier gave
14 of his money to Bryan. In the end, Bryan had thrice as much money as Xavier. How much money did Bryan have at first?
| |
Bryan |
Xavier |
Total |
| Before |
|
|
$348 |
| Change 1 |
- $19 |
+ $19 |
|
| After 1 |
|
4 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
3 p |
|
Comparing Bryan
and Xavier
in the end |
3 u |
1 u |
$348 |
The total amount that Xavier and Bryan had remains unchanged.
Total amount in the end
= 3 u + 1 u
= 4 u
4 u = 348
1 u = 348 ÷ 4 = 87
Amount that Bryan has in the end
= 3 u
= 3 x 87
= $261
Amount that Xavier has in the end
= 1 u
= $87
3 p = 1 u = 87
1 p = 87 ÷ 3 = 29
Amount that Xavier gave to Bryan
= 1 p
= 1 x 29
= $29
Amount that Bryan had at first
= 261 - 29 + 19
= $251
Answer(s): $251
