Tom and Zane had a total of $308. Tom gave $34 to Zane. In return, Zane gave
15 of his money to Tom. In the end, Tom had six times as much money as Zane. How much money did Tom have at first?
| |
Tom |
Zane |
Total |
| Before |
|
|
$308 |
| Change 1 |
- $34 |
+ $34 |
|
| After 1 |
|
5 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
4 p |
|
Comparing Tom
and Zane
in the end |
6 u |
1 u |
$308 |
The total amount that Zane and Tom had remains unchanged.
Total amount in the end
= 6 u + 1 u
= 7 u
7 u = 308
1 u = 308 ÷ 7 = 44
Amount that Tom has in the end
= 6 u
= 6 x 44
= $264
Amount that Zane has in the end
= 1 u
= $44
4 p = 1 u = 44
1 p = 44 ÷ 4 = 11
Amount that Zane gave to Tom
= 1 p
= 1 x 11
= $11
Amount that Tom had at first
= 264 - 11 + 34
= $287
Answer(s): $287
