Ryan and Fred had a total of $140. Ryan gave $20 to Fred. In return, Fred gave
16 of his money to Ryan. In the end, Ryan had six times as much money as Fred. How much money did Ryan have at first?
| |
Ryan |
Fred |
Total |
| Before |
|
|
$140 |
| Change 1 |
- $20 |
+ $20 |
|
| After 1 |
|
6 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
5 p |
|
Comparing Ryan
and Fred
in the end |
6 u |
1 u |
$140 |
The total amount that Fred and Ryan had remains unchanged.
Total amount in the end
= 6 u + 1 u
= 7 u
7 u = 140
1 u = 140 ÷ 7 = 20
Amount that Ryan has in the end
= 6 u
= 6 x 20
= $120
Amount that Fred has in the end
= 1 u
= $20
5 p = 1 u = 20
1 p = 20 ÷ 5 = 4
Amount that Fred gave to Ryan
= 1 p
= 1 x 4
= $4
Amount that Ryan had at first
= 120 - 4 + 20
= $136
Answer(s): $136
