Bobby and Xavier had a total of $310. Bobby gave $10 to Xavier. In return, Xavier gave
13 of his money to Bobby. In the end, Bobby had four times as much money as Xavier. How much money did Bobby have at first?
| |
Bobby |
Xavier |
Total |
| Before |
|
|
$310 |
| Change 1 |
- $10 |
+ $10 |
|
| After 1 |
|
3 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
2 p |
|
Comparing Bobby
and Xavier
in the end |
4 u |
1 u |
$310 |
The total amount that Xavier and Bobby had remains unchanged.
Total amount in the end
= 4 u + 1 u
= 5 u
5 u = 310
1 u = 310 ÷ 5 = 62
Amount that Bobby has in the end
= 4 u
= 4 x 62
= $248
Amount that Xavier has in the end
= 1 u
= $62
2 p = 1 u = 62
1 p = 62 ÷ 2 = 31
Amount that Xavier gave to Bobby
= 1 p
= 1 x 31
= $31
Amount that Bobby had at first
= 248 - 31 + 10
= $227
Answer(s): $227
