Neave and Liam had a total of $120. Neave gave $19 to Liam. In return, Liam gave
14 of his money to Neave. In the end, Neave had thrice as much money as Liam. How much money did Neave have at first?
| |
Neave |
Liam |
Total |
| Before |
|
|
$120 |
| Change 1 |
- $19 |
+ $19 |
|
| After 1 |
|
4 p |
|
| Change 2 |
+ 1 p |
- 1 p |
|
| After 2 |
|
3 p |
|
Comparing Neave
and Liam
in the end |
3 u |
1 u |
$120 |
The total amount that Liam and Neave had remains unchanged.
Total amount in the end
= 3 u + 1 u
= 4 u
4 u = 120
1 u = 120 ÷ 4 = 30
Amount that Neave has in the end
= 3 u
= 3 x 30
= $90
Amount that Liam has in the end
= 1 u
= $30
3 p = 1 u = 30
1 p = 30 ÷ 3 = 10
Amount that Liam gave to Neave
= 1 p
= 1 x 10
= $10
Amount that Neave had at first
= 90 - 10 + 19
= $99
Answer(s): $99
