Nora had 78 vanilla and cranberry croissants. After giving away
16 of her vanilla croissants and 12 of her cranberry croissants, she had an equal number of vanilla and cranberry croissants. How many cranberry croissants did she have at first?
|
Vanilla croissants |
Cranberry croissants |
Total |
Before |
6 u |
5 u + 12 |
78 |
Change |
- 1 u |
- 12 |
|
After |
5 u |
5 u |
|
Fraction of the vanilla croissants left
= 1 -
16=
56 The number of vanilla and cranberry croissants in the end is the same.
Total number of croissants at first
= 6 u + 5 u + 12
= 11 u + 12
11 u + 12 = 78
11 u = 78 - 12
11 u = 66
1 u = 66 ÷ 11 = 6
Number of cranberry croissants at first
= 5 u + 12
= 5 x 6 + 12
= 30 + 12
= 42
Answer(s): 42