Marion had 82 cheese and cranberry wafers. After giving away
13 of her cheese wafers and 12 of her cranberry wafers, she had an equal number of cheese and cranberry wafers. How many cranberry wafers did she have at first?
| |
Cheese wafers |
Cranberry wafers |
Total |
| Before |
3 u |
2 u + 12 |
82 |
| Change |
- 1 u |
- 12 |
|
| After |
2 u |
2 u |
|
Fraction of the cheese wafers left
= 1 -
13=
23 The number of cheese and cranberry wafers in the end is the same.
Total number of wafers at first
= 3 u + 2 u + 12
= 5 u + 12
5 u + 12 = 82
5 u = 82 - 12
5 u = 70
1 u = 70 ÷ 5 = 14
Number of cranberry wafers at first
= 2 u + 12
= 2 x 14 + 12
= 28 + 12
= 40
Answer(s): 40
