Ivory had 111 banana and apricot croissants. After giving away
15 of her banana croissants and 12 of her apricot croissants, she had an equal number of banana and apricot croissants. How many apricot croissants did she have at first?
| |
Banana croissants |
Apricot croissants |
Total |
| Before |
5 u |
4 u + 12 |
111 |
| Change |
- 1 u |
- 12 |
|
| After |
4 u |
4 u |
|
Fraction of the banana croissants left
= 1 -
15=
45 The number of banana and apricot croissants in the end is the same.
Total number of croissants at first
= 5 u + 4 u + 12
= 9 u + 12
9 u + 12 = 111
9 u = 111 - 12
9 u = 99
1 u = 99 ÷ 9 = 11
Number of apricot croissants at first
= 4 u + 12
= 4 x 11 + 12
= 44 + 12
= 56
Answer(s): 56
