Kimberly had 75 cherry and strawberry croissants. After giving away
15 of her cherry croissants and 12 of her strawberry croissants, she had an equal number of cherry and strawberry croissants. How many strawberry croissants did she have at first?
|
Cherry croissants |
Strawberry croissants |
Total |
Before |
5 u |
4 u + 12 |
75 |
Change |
- 1 u |
- 12 |
|
After |
4 u |
4 u |
|
Fraction of the cherry croissants left
= 1 -
15=
45 The number of cherry and strawberry croissants in the end is the same.
Total number of croissants at first
= 5 u + 4 u + 12
= 9 u + 12
9 u + 12 = 75
9 u = 75 - 12
9 u = 63
1 u = 63 ÷ 9 = 7
Number of strawberry croissants at first
= 4 u + 12
= 4 x 7 + 12
= 28 + 12
= 40
Answer(s): 40