Kimberly had 112 apricot and vanilla shortbreads. After giving away
16 of her apricot shortbreads and 13 of her vanilla shortbreads, she had an equal number of apricot and vanilla shortbreads. How many vanilla shortbreads did she have at first?
| |
Apricot shortbreads |
Vanilla shortbreads |
Total |
| Before |
6 u |
5 u + 13 |
112 |
| Change |
- 1 u |
- 13 |
|
| After |
5 u |
5 u |
|
Fraction of the apricot shortbreads left
= 1 -
16=
56 The number of apricot and vanilla shortbreads in the end is the same.
Total number of shortbreads at first
= 6 u + 5 u + 13
= 11 u + 13
11 u + 13 = 112
11 u = 112 - 13
11 u = 99
1 u = 99 ÷ 11 = 9
Number of vanilla shortbreads at first
= 5 u + 13
= 5 x 9 + 13
= 45 + 13
= 58
Answer(s): 58
