Jean had 53 apricot and blueberry croissants. After giving away
13 of her apricot croissants and 13 of her blueberry croissants, she had an equal number of apricot and blueberry croissants. How many blueberry croissants did she have at first?
| |
Apricot croissants |
Blueberry croissants |
Total |
| Before |
3 u |
2 u + 13 |
53 |
| Change |
- 1 u |
- 13 |
|
| After |
2 u |
2 u |
|
Fraction of the apricot croissants left
= 1 -
13=
23 The number of apricot and blueberry croissants in the end is the same.
Total number of croissants at first
= 3 u + 2 u + 13
= 5 u + 13
5 u + 13 = 53
5 u = 53 - 13
5 u = 40
1 u = 40 ÷ 5 = 8
Number of blueberry croissants at first
= 2 u + 13
= 2 x 8 + 13
= 16 + 13
= 29
Answer(s): 29
