Elyse and Liam had the same amount of savings at first. Then Elyse spent
14 of her savings and Liam spent
56 of his savings. If Elyse spent $623 less than Liam, how much did each of them have at first?
| |
Elyse |
Liam |
| Before |
4x3 =
12 u |
6x2 =
12 u |
| Change |
1x3 =
- 3 u |
5x2 =
- 10 u |
| After |
9 u |
2 u |
The amount that Elyse and Liam had at first is the same. Make the amount that Elyse and Liam each had the same. LCM of 4 and 6 is 12.
Amount that Elyse spent less than Liam
= 10 u - 3 u
= 7 u
7 u = 623
1 u = 623 ÷ 7 = 89
Amount that each of them had at first
= 12 u
= 12 x 89
= $1068
Answer(s): $1068
