Opal and Ken had the same amount of savings at first. Then Opal spent
16 of her savings and Ken spent
34 of his savings. If Opal spent $1274 less than Ken, how much did each of them have at first?
| |
Opal |
Ken |
| Before |
6x2 =
12 u |
4x3 =
12 u |
| Change |
1x2 =
- 2 u |
3x3 =
- 9 u |
| After |
10 u |
3 u |
The amount that Opal and Ken had at first is the same. Make the amount that Opal and Ken each had the same. LCM of 6 and 4 is 12.
Amount that Opal spent less than Ken
= 9 u - 2 u
= 7 u
7 u = 1274
1 u = 1274 ÷ 7 = 182
Amount that each of them had at first
= 12 u
= 12 x 182
= $2184
Answer(s): $2184
