Sean and Paul had 54 markers. After Sean gave 15 markers to Paul. Paul, in return, gave half of his markers to Sean. In the end, Sean had twice as many markers as Paul. How many markers did Sean have at first?
| |
Sean |
Paul |
Total |
| Before |
1 u + 15 |
2 u - 15 |
54 |
| Change 1 |
- 15 |
+ 15 |
|
| After 1 |
1 u |
2 u |
|
| Change 2 |
+ 1 u |
- 1 u |
|
| After 2 |
2 u |
1 u |
54 |
Total number of markers that Sean and Paul had at first and in the end remains unchanged.
Total number of markers
= 2 u + 1 u
= 3 u
1 u = 54 ÷ 3 = 18
Number of markers that Sean had at first
= 1 u + 15
= 18 + 15
= 33
Answer(s): 33
