Andy and Liam had 66 markers. After Andy gave 24 markers to Liam. Liam, in return, gave half of his markers to Andy. In the end, Andy had twice as many markers as Liam. How many markers did Andy have at first?
| |
Andy |
Liam |
Total |
| Before |
1 u + 24 |
2 u - 24 |
66 |
| Change 1 |
- 24 |
+ 24 |
|
| After 1 |
1 u |
2 u |
|
| Change 2 |
+ 1 u |
- 1 u |
|
| After 2 |
2 u |
1 u |
66 |
Total number of markers that Andy and Liam had at first and in the end remains unchanged.
Total number of markers
= 2 u + 1 u
= 3 u
1 u = 66 ÷ 3 = 22
Number of markers that Andy had at first
= 1 u + 24
= 22 + 24
= 46
Answer(s): 46
