Xavier and Henry had 75 pens. After Xavier gave 20 pens to Henry. Henry, in return, gave half of his pens to Xavier. In the end, Xavier had twice as many pens as Henry. How many pens did Xavier have at first?
| |
Xavier |
Henry |
Total |
| Before |
1 u + 20 |
2 u - 20 |
75 |
| Change 1 |
- 20 |
+ 20 |
|
| After 1 |
1 u |
2 u |
|
| Change 2 |
+ 1 u |
- 1 u |
|
| After 2 |
2 u |
1 u |
75 |
Total number of pens that Xavier and Henry had at first and in the end remains unchanged.
Total number of pens
= 2 u + 1 u
= 3 u
1 u = 75 ÷ 3 = 25
Number of pens that Xavier had at first
= 1 u + 20
= 25 + 20
= 45
Answer(s): 45
