Ken and Julian had 60 markers. After Ken gave 17 markers to Julian. Julian, in return, gave half of his markers to Ken. In the end, Ken had twice as many markers as Julian. How many markers did Ken have at first?
| |
Ken |
Julian |
Total |
| Before |
1 u + 17 |
2 u - 17 |
60 |
| Change 1 |
- 17 |
+ 17 |
|
| After 1 |
1 u |
2 u |
|
| Change 2 |
+ 1 u |
- 1 u |
|
| After 2 |
2 u |
1 u |
60 |
Total number of markers that Ken and Julian had at first and in the end remains unchanged.
Total number of markers
= 2 u + 1 u
= 3 u
1 u = 60 ÷ 3 = 20
Number of markers that Ken had at first
= 1 u + 17
= 20 + 17
= 37
Answer(s): 37
