Seth had $56 more than Irene. After Irene spent
13 of her money, Seth had five times as much money as Irene. How much money did Seth have at first?
| |
Seth |
Irene |
| Before |
10 u |
3 u |
| Change |
|
- 1 u |
| After |
10 u |
2 u |
Amount that Seth had in the end
= 5 x 2 u
= 10 u
If Irene had another $56 at first, the amounts that Seth and Irene each had at first will be the same.
10 u = 3 u + 56
10 u - 3 u = 56
7 u = 56
1 u = 56 ÷ 7 = 8
Amount Seth had at first
= 10 u
= 10 x 8
= $80
Answer(s): $80
