Eric had $48 more than Pamela. After Pamela spent
27 of her money, Eric had twice as much money as Pamela. How much money did Eric have at first?
| |
Eric |
Pamela |
| Before |
10 u |
7 u |
| Change |
|
- 2 u |
| After |
10 u |
5 u |
Amount that Eric had in the end
= 2 x 5 u
= 10 u
If Pamela had another $48 at first, the amounts that Eric and Pamela each had at first will be the same.
10 u = 7 u + 48
10 u - 7 u = 48
3 u = 48
1 u = 48 ÷ 3 = 16
Amount Eric had at first
= 10 u
= 10 x 16
= $160
Answer(s): $160
