Dylan had $40 more than Shannon. After Shannon spent
13 of her money, Dylan had four times as much money as Shannon. How much money did Dylan have at first?
| |
Dylan |
Shannon |
| Before |
8 u |
3 u |
| Change |
|
- 1 u |
| After |
8 u |
2 u |
Amount that Dylan had in the end
= 4 x 2 u
= 8 u
If Shannon had another $40 at first, the amounts that Dylan and Shannon each had at first will be the same.
8 u = 3 u + 40
8 u - 3 u = 40
5 u = 40
1 u = 40 ÷ 5 = 8
Amount Dylan had at first
= 8 u
= 8 x 8
= $64
Answer(s): $64
