In a weight-lifting competition, the first weight-lifter lifted a mass of 500 kg 60 g while the second weight-lifter lifted 70 kg 600 g more. Given that the third weight-lifter lifted 60 kg 700 g more than the second weight-lifter, what is the total mass that the 3 of them lifted? (Give the answer in kg and g.)
1 kg = 1000 g

500 kg 60 g = 500 x 1000 + 60 = 500060 g
70 kg 600 g = 70 x 1000 + 600 = 70600 g
60 kg 700 g = 60 x 1000 + 700 = 60700 g

Mass that the first lifter lifted = 500060 g

Mass that the second weight-lifter lifted
= 500060 + 70600
= 570660 g

Mass that the third weight-lifter lifted
= 570660 + 60700
= 631360 g

Total mass that the 3 of them lifted
= 500060 + 570660 + 631360
= 1702080 g
= 1702 kg 80 g

Answer(s): 1702 kg 80 g