In a weight-lifting competition, the first weight-lifter lifted a mass of 600 kg 40 g while the second weight-lifter lifted 60 kg 400 g more. Given that the third weight-lifter lifted 50 kg 600 g more than the second weight-lifter, what is the total mass that the 3 of them lifted? (Give the answer in kg and g.)
1 kg = 1000 g

600 kg 40 g = 600 x 1000 + 40 = 600040 g
60 kg 400 g = 60 x 1000 + 400 = 60400 g
50 kg 600 g = 50 x 1000 + 600 = 50600 g

Mass that the first lifter lifted = 600040 g

Mass that the second weight-lifter lifted
= 600040 + 60400
= 660440 g

Mass that the third weight-lifter lifted
= 660440 + 50600
= 711040 g

Total mass that the 3 of them lifted
= 600040 + 660440 + 711040
= 1971520 g
= 1971 kg 520 g

Answer(s): 1971 kg 520 g