In a weight-lifting competition, the first weight-lifter lifted a mass of 500 kg 50 g while the second weight-lifter lifted 60 kg 500 g more. Given that the third weight-lifter lifted 40 kg 600 g more than the second weight-lifter, what is the total mass that the 3 of them lifted? (Give the answer in kg and g.)
1 kg = 1000 g

500 kg 50 g = 500 x 1000 + 50 = 500050 g
60 kg 500 g = 60 x 1000 + 500 = 60500 g
40 kg 600 g = 40 x 1000 + 600 = 40600 g

Mass that the first lifter lifted = 500050 g

Mass that the second weight-lifter lifted
= 500050 + 60500
= 560550 g

Mass that the third weight-lifter lifted
= 560550 + 40600
= 601150 g

Total mass that the 3 of them lifted
= 500050 + 560550 + 601150
= 1661750 g
= 1661 kg 750 g

Answer(s): 1661 kg 750 g