Dana places 3 packets an equal distance from one another. The distance between the first packet and the third packet is 140 cm. If Dana adds another 11 packets that are equal distance apart,
- How many gaps will there be between the eleventh packet and the fourteenth packet?
- What is the distance between the 11th packet and the 14th packet?
(a)
Number of gaps between 3 packets
= 3 - 1
= 2
Distance between two packets
= 140 ÷ 2
= 70 cm
Number of gaps between the eleventh and the fourteenth packet
= 14 - 11
= 3
(b)
Distance between the eleventh and the fourteenth packet
= 3 x 70
= 210 cm
Answer(s): (a) 3; (b) 210 cm