Diana places 3 packets an equal distance from one another. The distance between the first packet and the third packet is 110 cm. If Diana adds another 10 packets that are equal distance apart,
- How many gaps will there be between the tenth packet and the thirteenth packet?
- What is the distance between the 10th packet and the 13th packet?
(a)
Number of gaps between 3 packets
= 3 - 1
= 2
Distance between two packets
= 110 ÷ 2
= 55 cm
Number of gaps between the tenth and the thirteenth packet
= 13 - 10
= 3
(b)
Distance between the tenth and the thirteenth packet
= 3 x 55
= 165 cm
Answer(s): (a) 3; (b) 165 cm