Linda places 5 packets an equal distance from one another. The distance between the first packet and the fifth packet is 120 cm. If Linda adds another 13 packets that are equal distance apart,
- How many gaps will there be between the thirteenth packet and the eighteenth packet?
- What is the distance between the 13th packet and the 18th packet?
(a)
Number of gaps between 5 packets
= 5 - 1
= 4
Distance between two packets
= 120 ÷ 4
= 30 cm
Number of gaps between the thirteenth and the eighteenth packet
= 18 - 13
= 5
(b)
Distance between the thirteenth and the eighteenth packet
= 5 x 30
= 150 cm
Answer(s): (a) 5; (b) 150 cm