Victoria places 5 packets an equal distance from one another. The distance between the first packet and the fifth packet is 120 cm. If Victoria adds another 15 packets that are equal distance apart,
- How many gaps will there be between the fifteenth packet and the twentieth packet?
- What is the distance between the 15th packet and the 20th packet?
(a)
Number of gaps between 5 packets
= 5 - 1
= 4
Distance between two packets
= 120 ÷ 4
= 30 cm
Number of gaps between the fifteenth and the twentieth packet
= 20 - 15
= 5
(b)
Distance between the fifteenth and the twentieth packet
= 5 x 30
= 150 cm
Answer(s): (a) 5; (b) 150 cm